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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A ball dropped from a height of 2 m rebounds to a height of 1.5 m after hitting the ground. Then the percentage of energy lost is

Answer: (A)

Solution

Percentage energy lost = [(mgh − mgh')/mgh] × 100 = [(2−1.5)/2]×100 = 25%.

Question ID VK-153607