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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

Two balls of masses 2 g and 6 g are moving with KE in the ratio of 3:1. What is the ratio of their linear momenta? [BVP 2010]

Answer: (A)

Solution

p = √(2mK). p₁/p₂ = √[(m₁K₁)/(m₂K₂)] = √[(2×3)/(6×1)] = √(6/6) = 1, i.e., ratio 1:1.

Question ID VK-153611