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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of mass 3 kg acted upon by a constant force is displaced by S metre, given by the relation S = ⅓t², where t is in second. Work done by the force in 2 seconds is

Answer: (A)

Solution

v = dS/dt = (2/3)t; at t=2, v=4/3 ms⁻¹; a = 2/3 ms⁻². F = ma = 3×2/3 =

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Question ID VK-153613