JEE Main Physics question
An engine pumps up 100 kg of water through a height of 10 m in 5 s. Given that the efficiency of the engine is 60%, if g = 10 ms⁻², the power of the engine is [BCECE 2008]
Answer: (A)
Solution
Useful power = mgh/t = (100)(10)(10)/5 = 2000 W. Actual power = (useful power)/η = 2000/0.6 ≈ 3333 W ≈ 3.3 kW.