JEE Main Physics question
A man does a given amount of work in 10 s. Another man does the same amount of work in 20 s. The ratio of the output power of the first man to the second is [J & K CET 2005]
Answer: (C)
Solution
Power ∝ 1/time for the same work done. P₁/P₂ = t₂/t₁ = 20/10 = 2/1.