JEE Main Physics question
A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is
Answer: (C)
Solution
v = m₁u₁/(m₁+m₂) = (0.5×2)/1.5 = 2/3 ms⁻¹. = ½(0.5)(2²) = 1 J. = ½(1.5)(2/3)² = 1/3 J. Loss = 1 − 1/3 = 2/3 ≈ 0.67 J.