JEE Main Physics question
A bullet of mass 20 g moving with 600 ms⁻¹ collides with a block of mass 4 kg hanging with a string. What is the velocity of the bullet when it comes out of the block, if the block rises to a height of 0.2 m after the collision? [UP SEE 2006]
Answer: (A)
Solution
Block's velocity just after impact (from pendulum rise): v₂ = √(2gh) = √(2×10×0.2) =
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