JEE Main Physics question
A body of mass 4 kg moving with velocity 12 ms⁻¹ collides with another body of mass 6 kg at rest. If the two bodies stick together after collision, then the loss of kinetic energy of the system is
Answer: (B)
Solution
v = (4×12)/10 = 4.8 ms⁻¹. = ½(4)(12²) = 288 J. = ½(10)(4.8²) = 115.2 J. Loss = 288 − 115.2 = 172.8 J.