JEE Main Physics question
A bomb at rest explodes into 3 parts of the same mass. The momenta of 2 parts are −2pî and pĵ. The momentum of the third part will have a magnitude of
Answer: (C)
Solution
Momentum conservation (initially zero): **p₃** = −(−2pî + pĵ) = (2pî − pĵ). |**p₃**| = √(4p²+p²) = p√5.