JEE Main Physics question
In two separate collisions, the coefficients of restitution e₁ and e₂ are in the ratio 3:1. In the first collision, the relative velocity of approach is twice the relative velocity of separation, then the ratio between the relative velocity of approach and the relative velocity of separation in the second collision is
Answer: (D)
Solution
e₁ = (relative velocity of separation)/(relative velocity of approach) = 1/2. Given e₁:e₂ = 3:1, e₂ =
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