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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A car weighing 1400 kg is moving at a speed of 54 km/h up a hill when the motor stops. If it is just able to reach the destination which is at a height of 10 m above the point, then the work done against friction (negative of the work done by friction) is (g = 10 ms⁻²)

Answer: (C)

Solution

Speed = 54 km/h = 15 ms⁻¹. By the work-energy theorem (final KE = 0): ½mv² = mgh +

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Question ID VK-153693