JEE Main Physics question
The velocity of a 2 kg body is changed from (4î + 3ĵ) ms⁻¹ to 6 ĵ ms⁻¹. The work done on the body is
Answer: (B)
Solution
|v₁|² = 4²+3² = 25, |v₂|² = 6² = 36. W = ΔKE = ½(2)(36−25) = 11 J.
The velocity of a 2 kg body is changed from (4î + 3ĵ) ms⁻¹ to 6 ĵ ms⁻¹. The work done on the body is
|v₁|² = 4²+3² = 25, |v₂|² = 6² = 36. W = ΔKE = ½(2)(36−25) = 11 J.