JEE Main Physics question
A man, by working a hand pump fixed to a well, pumps out 10 m³ of water in 1 s. If the water in the well is 10 m below ground level, then the work done by the man is (g = 10 ms⁻²)
Answer: (D)
Solution
Mass of water = 10 m³ × 1000 kg/m³ = 10⁴ kg. W = mgh = 10⁴×10×10 = 10⁶ J.