JEE Main Physics question

A force F = Ay² + By + C acts on a body in the y-direction. The work done by this force during a displacement from y = −a to y = a is

Answer: (B)

Solution

W = ∫₋ₐᵃ (Ay²+By+C) dy = [Ay³/3 + By²/2 + Cy]₋ₐᵃ = (2Aa³/3 + 0 + 2Ca), since the By²/2 terms cancel (even function evaluated

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Question ID VK-153702