JEE Main Physics question
A body of mass 10 kg is moving on a horizontal surface by applying a force of 10 N in the forward direction. If the body moves with constant velocity, the work done by the force of friction for a displacement of 2 m is
Answer: (A)
Solution
Constant velocity ⟹ net force zero ⟹ friction = applied force = 10 N, opposing the motion. = −10×2 = −20 J.