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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

In a children's park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenths of his weight. The work done by the slide on the boy as he comes down is

Answer: (C)

Solution

Frictional force F = (3/10)(200) = 60 N, opposing the boy's motion down the

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Question ID VK-153707