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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A 2.0 kg block is dropped from a height of 40 cm onto a spring of spring constant k = 1960 N m⁻¹. Find the maximum distance the spring is compressed.

Answer: (D)

Solution

Energy conservation: mg(h+x) = ½kx² ⟹ kx² − 2mgx − 2mgh = 0. With m=2, g=9.8, h=0.4, k=1960: 1960x²

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Question ID VK-153714