JEE Main Physics question
A force of 5 N moves a particle through a distance of 10 m. If 25 J of work is performed, then the angle between the force and the direction of motion is
Answer: (D)
Solution
cosθ = W/(Fs) = 25/(5×10) = 0.5 ⟹ θ = 60°.
A force of 5 N moves a particle through a distance of 10 m. If 25 J of work is performed, then the angle between the force and the direction of motion is
cosθ = W/(Fs) = 25/(5×10) = 0.5 ⟹ θ = 60°.