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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A 5 kg brick of 20 cm × 10 cm × 8 cm dimensions lying on its largest base is now made to stand with length vertical. If g = 10 ms⁻², then the amount of work done is

Answer: (A)

Solution

Lying on its largest base (20×10 face down), the centre of gravity height is 8/2 = 4 cm. Standing on the smallest face

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Question ID VK-153717