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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A mass M is lowered with the help of a string by a distance h at a constant acceleration g/2. The work done by the string will be

Answer: (B)

Solution

Mg − T = M(g/2) ⟹ T = Mg/2. The tension acts upward (opposite the downward displacement h): W = −Th = −Mgh/2.

Question ID VK-153719