JEE Main Physics question
A man throws a piece of stone to a height of 12 m where it reaches with a speed of 12 ms⁻¹. If he throws the same stone such that it just reaches that height, the percentage of energy saved is nearly
Answer: (B)
Solution
Energy in the first throw = ½mv² + mgh = ½m(144) + m(10)(12) = 72m+120m = 192m (taking g≈10). Energy in the
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