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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of mass 2 kg is thrown up vertically with kinetic energy of 490 J. The height at which the kinetic energy of the body becomes half of its original value is

Answer: (B)

Solution

At height h, KE = 245 J, so PE gained = 490−245 = 245 J = mgh = 2(9.8)h ⟹ h = 245/19.6 = 12.5 m ≈ 12.25 m (using g=10: h=245/20=12.25 m).

Question ID VK-153735