JEE Main Physics question
A 50 g bullet moving with a velocity of 10 ms⁻¹ gets embedded into a 950 g stationary body. The loss in KE of the system will be
Answer: (A)
Solution
v = (0.05×10)/1 = 0.5 ms⁻¹. = ½(0.05)(100) = 2.5 J. = ½(1)(0.25) = 0.125 J. Loss = (2.5−0.125)/2.5 × 100 = 95%.