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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration is varying with time t as = k²rt². The power is

Answer: (B)

Solution

= v²/r = k²rt² ⟹ v = krt. Tangential acceleration = dv/dt = kr. Power is delivered

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Question ID VK-153780