JEE Main Physics question
Power supplied to a particle of mass 2 kg varies with time as P = (3/2)t² watt, where t is in second. If the velocity of the particle at t = 0 is v = 0, the velocity of the particle at t = 2 s will be
Answer: (C)
Solution
By the work-energy theorem, ½mv² = ∫₀² P dt = ∫₀² (3/2)t² dt = (1/2)(t³)|₀² = (1/2)(8) = 4. So ½(2)v² = 4 ⟹ v² = 4 ⟹ v = 2 ms⁻¹.