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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

Power applied to a particle varies with time as P = (3t² − 2t + 1) watt, where t is in second. Find the change in its kinetic energy between t = 2 s and t = 4 s.

Answer: (B)

Solution

ΔK = ∫₂⁴ (3t²−2t+1) dt = [t³−t²+t]₂⁴ = (64−16+4) − (8−4+2) = 52−6 = 46 J.

Question ID VK-153785