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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A body of mass M is hung by a long thread and a bullet of mass m hits it horizontally with a velocity v and gets embedded in the body. Then for the body and the bullet system,

Answer: (D)

Solution

Momentum conservation: mv = (M+m)V ⟹ V = mv/(M+m). Final KE = ½(M+m)V² = ½(M+m)[mv/(M+m)]² = m²v²/[2(M+m)].

Question ID VK-153789