JEE Main Physics question
A ball is dropped from a height of 20 cm. The ball rebounds to a height of 10 cm. What is the loss of energy?
Answer: (C)
Solution
% loss = [(h₁−h₂)/h₁]×100 = [(20−10)/20]×100 = 50%.
A ball is dropped from a height of 20 cm. The ball rebounds to a height of 10 cm. What is the loss of energy?
% loss = [(h₁−h₂)/h₁]×100 = [(20−10)/20]×100 = 50%.