JEE Main Physics question
A bob of mass m accelerates uniformly from rest to v₁ in time t₁. As a function of t, the instantaneous power delivered to the body is
Answer: (D)
Solution
(Same method as Q94.) a=v₁/t₁, v(t)=v₁t/t₁, so P=Fv=m(v₁/t₁)(v₁t/t₁) = mv₁²t/t₁².