JEE Main Physics question
A body of mass 3 kg acted upon by a constant force is displaced by s metre, given by the relation s = t²/3, where t is in second. Work done by the force in 2 s is
Answer: (A)
Solution
(Same as Q79.) v = (2/3)t, F = ma = 3×(2/3) = 2 N, work = ∫₀² F·v dt = ∫₀² 2(2/3)t dt = (4/3)(2) = 8/3 J.