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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of mass 3 kg is under a force which causes a displacement in it given by s = t²/3 (in m). Find the work done by the force in 2 s.

Answer: (D)

Solution

v = ds/dt = 2t/3, a = 2/3. F = ma = 3×(2/3) = 2 N. s(0) = 0, s(2) = 4/3 m. W = F·s = 2×(4/3) = 8/3 ≈ 2.6 J.

Question ID VK-153807