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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A box of mass 50 kg is pulled up on an incline 12 m long and 2 m high by a constant force of 100 N from rest. It acquires a velocity of 2 ms⁻¹ on reaching the top. Work done against friction is (g = 10 ms⁻²)

Answer: (B)

Solution

Work by applied force = 100×12 = 1200 J. This equals PE gained + KE gained + work

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Question ID VK-153813