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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A car of mass 1000 kg moves at a constant speed of 20 ms⁻¹ up an incline. Assume that the frictional force is 200 N and that sinθ = 1/20, where θ is the angle of the incline to the horizontal. g = 10 ms⁻². Find the power developed by the engine.

Answer: (A)

Solution

At constant speed, driving force = (mg sinθ + friction) = (1000×10×1/20) + 200 = 500+200 = 700 N. P = Fv = 700×20 = 14000 W = 14 kW.

Question ID VK-153814