JEE Main Physics question
The area of the acceleration-displacement curve of a body gives
Answer: (C)
Solution
∫a dx = ∫(dv/dt)dx = ∫v dv = (v² − u²)/2, which is the change in kinetic energy per unit mass.
The area of the acceleration-displacement curve of a body gives
∫a dx = ∫(dv/dt)dx = ∫v dv = (v² − u²)/2, which is the change in kinetic energy per unit mass.