JEE Main Physics question
A body of mass 10 kg at rest is acted upon simultaneously by two forces 4 N and 3 N at right angles to each other. The kinetic energy of the body at the end of 10 sec is
Answer: (D)
Solution
Net force = √(4² + 3²) = 5 N, so a = F/m = 5/10 = 0.5 m/s². Velocity after 10 s = at = 5 m/s. KE = ½mv² = ½(10)(5)² = 125 J.