JEE Main Physics question

Physics Work, Energy and Power JEE Main

A cord is used to lower vertically a block of mass M by a distance d with constant downward acceleration g/4. Work done by the cord on the block is

(A)Mg(d/4)
(B)3Mg(d/4)
(C)−3Mg(d/4)Correct
(D)Mgd

Answer: (C)

Solution

Applying Newton's second law on the block moving down with acceleration g/4: Mg − T = M(g/4) ⟹ T = (3/4)Mg. The cord's

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-153848