Test SeriesFree PYQsExamsPricing

JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s²)

Answer: (A)

Solution

Initial KE = ½(1)(20)² = 200 J. Gravitational PE gained at height 18 m = mgh = 1

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-153853