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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A force acts on a 30 g particle in such a way that the position of the particle as a function of time is given by x = 3t − 4t² + t³, where x is in metres and t is in seconds. The work done during the first 4 seconds is

Answer: (A)

Solution

v = dx/dt = 3 − 8t + 3t². At t = 0, v₀ = 3 m/s; at t = 4, v₄ = 3 − 32 + 48 = 19 m/s.

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Question ID VK-153860