JEE Main Physics question
A particle moves under the effect of a force F = Cx from x = 0 to x = x₁. The work done in the process is
Answer: (B)
Solution
W = ∫₀^x₁ Cx dx = C[x²/2]₀^x₁ = ½Cx₁².
A particle moves under the effect of a force F = Cx from x = 0 to x = x₁. The work done in the process is
W = ∫₀^x₁ Cx dx = C[x²/2]₀^x₁ = ½Cx₁².