JEE Main Physics question
A variable force, given by the 2-dimensional vector F = (3x²î + 4ĵ), acts on a particle (F in newton, x in metre). What is the change in the kinetic energy of the particle as it moves from the point with coordinates (2,3) to (3,0)? (Coordinates in metres)
Answer: (C)
Solution
W = ∫F·dr = ∫(3x²dx + 4dy) = [x³ + 4y] from (2,3) to (3,0) = (27 + 0) − (8 + 12) = 27 −
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