JEE Main Physics question
A spring with spring constant k is extended from x = 0 to x = x₁. The work done will be
Answer: (B)
Solution
W = ∫₀^x₁ kx dx = ½kx₁², the standard elastic potential energy stored in the spring.
A spring with spring constant k is extended from x = 0 to x = x₁. The work done will be
W = ∫₀^x₁ kx dx = ½kx₁², the standard elastic potential energy stored in the spring.