JEE Main Physics question
The potential energy of a body is given by, U = A − Bx² (where x is the displacement). The magnitude of force acting on the particle is [BHU 2002]
Answer: (B)
Solution
F = −dU/dx = −(−2Bx) = 2Bx, so F ∝ x.
The potential energy of a body is given by, U = A − Bx² (where x is the displacement). The magnitude of force acting on the particle is [BHU 2002]
F = −dU/dx = −(−2Bx) = 2Bx, so F ∝ x.