JEE Main Physics question
A body of mass 0.1 kg moving with a velocity of 10 m/s hits a spring (fixed at the other end) of force constant 1000 N/m and comes to rest after compressing the spring. The compression of the spring is
Answer: (B)
Solution
½mv² = ½kx² ⟹ x = v√(m/k) = 10√(0.1/1000) = 10√(10⁻⁴) = 10 × 0.01 = 0.1 m.