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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A mass of 0.5 kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearly weightless spring of force constant k = 50 N/m. The maximum compression of the spring would be

Answer: (A)

Solution

The kinetic energy converts entirely into spring PE: ½mv² = ½kx² ⟹ x = v√(m/k) = 1.5√(0.5/50) = 1.5√0.01 = 1.5 × 0.1 = 0.15 m.

Question ID VK-153900