JEE Main Physics question
If a body of mass 200 g falls from a height 200 m and its total PE is converted into KE at the point of contact with the earth's surface, then what is the decrease in PE of the body at the contact (g = 10 m/s²)
Answer: (B)
Solution
ΔU = mgh = 0.2 × 10 × 200 = 400 J.