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JEE Main Physics question

PhysicsSystems of Particles and Rotational MotionJEE Main

A bomb of 12 kg divides into two parts whose ratio of masses is 1 : 3. If the kinetic energy of the smaller part is 216 J, then the momentum of the bigger part in kg-m/sec will be [RPET 1997]

Answer: (A)

Solution

The masses are m₁ = 3 kg and m₂ = 9 kg (in ratio 1:3). From ½m₁v₁² = 216 J: v₁ = 12 m/s, so its momentum is 3 × 12 = 36

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Question ID VK-153916