JEE Main Physics question
If the water falls from a dam into a turbine wheel 19.6 m below, then the velocity of water at the turbine is (g = 9.8 m/s²) [AIIMS 1998]
Answer: (B)
Solution
By conservation of energy, the loss in PE converts to KE: mgh = ½mv² ⟹ v = √(2gh) = √(2 × 9.8 × 19.6) = 19.6 m/s.