JEE Main Physics question
The decrease in the potential energy of a ball of mass 20 kg which falls from a height of 50 cm is [AIIMS 1997]
Answer: (B)
Solution
ΔU = mgh = 20 × 9.8 × 0.5 = 98 J.
The decrease in the potential energy of a ball of mass 20 kg which falls from a height of 50 cm is [AIIMS 1997]
ΔU = mgh = 20 × 9.8 × 0.5 = 98 J.