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JEE Main Physics question

PhysicsWork, Energy and PowerJEE Main

A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0 m. How much energy is dissipated by air drag acting on the ball during the ascent? [AMU (Med.) 2000]

Answer: (D)

Solution

Without air drag, the maximum height would be H = u²/(2g) = (14)²/(2×9.8) = 10 m. The ball actually reaches only 8 m,

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Question ID VK-153942