JEE Main Physics question
If the K.E. of a body is increased by 300%, its momentum will increase by
Answer: (A)
Solution
p ∝ √E. If E₂ = E + 300% of E = 4E, then p₂/p₁ = √(E₂/E₁) = √4 = 2, i.e. momentum increases by 100%.
If the K.E. of a body is increased by 300%, its momentum will increase by
p ∝ √E. If E₂ = E + 300% of E = 4E, then p₂/p₁ = √(E₂/E₁) = √4 = 2, i.e. momentum increases by 100%.